{"id":18129,"date":"2024-04-26T09:10:27","date_gmt":"2024-04-26T09:10:27","guid":{"rendered":"https:\/\/soicau5068.minhngocxoso.com\/?p=18129"},"modified":"2024-04-26T09:10:27","modified_gmt":"2024-04-26T09:10:27","slug":"phuong-phap-soi-cau-dac-biet-giup-ban-trung-lon-thang-to","status":"publish","type":"post","link":"https:\/\/dudoanbachthu.com\/phuong-phap-soi-cau-dac-biet-giup-ban-trung-lon-thang-to\/","title":{"rendered":"ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u \u0111\u1eb7c bi\u1ec7t gi\u00fap b\u1ea1n tr\u00fang l\u1edbn, th\u1eafng to"},"content":{"rendered":"
<\/p>\n\n\n
M\u00ecnh t\u00ecnh c\u1edd s\u01b0u t\u1ea7m \u0111\u01b0\u1ee3c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, tuy n\u00f3 kh\u00f4ng d\u1ef1a v\u00e0o th\u1ed1ng k\u00ea x\u00e1c su\u1ea5t khoa h\u1ecdc nh\u01b0ng n\u00f3 l\u1ea1i ch\u00ednh x\u00e1c m\u1ed9t c\u00e1ch k\u1ef3 l\u1ea1. Ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u n\u00e0y d\u1ef1a v\u00e0o t\u1ed5ng hi\u1ec7u gi\u1eefa c\u00e1c v\u1ecb tr\u00ed c\u1ee7a c\u00e1c s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t. \u0110\u00e2y s\u1ebd l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u b\u1ea1ch th\u1ee7 \u0111\u1ec1, song th\u1ee7 \u0111\u1ec1\u2026 hay cho anh em tham kh\u1ea3o.<\/p>\n\n\n\n
B\u01b0\u1edbc 1: Ta x\u00e9t gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 trong h\u00f4m nay: ABCDE
V\u00ed d\u1ee5: Ng\u00e0y 23\/05\/2024 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t: 62307.<\/p>\n\n\n\n
G\u00e1n bi\u1ebfn gi\u1ea3i \u0111\u1eb7c bi\u1ec7t
B\u01b0\u1edbc 2: Ta l\u1ea5y hi\u1ec7u A \u2013 C = X v\u00e0 E \u2013 C = Y. Ta s\u1ebd \u0111\u01b0\u1ee3c l\u00f4 XY.
V\u00ed d\u1ee5: \u1ede ng\u00e0y 23\/05\/2024 Ta c\u00f3 A = 6, C=3, E= 7. Ta c\u00f3:
X = 6-3= 3
Y = 7-3 =4
V\u1eady ta \u0111\u01b0\u1ee3c l\u00f4 34.
Ch\u00fa \u00fd: N\u1ebfu A l\u1edbn h\u01a1n C th\u00ec X = A \u2013 C. C\u00f2n n\u1ebfu A b\u00e9 h\u01a1n C th\u00ec X = C \u2013 A. T\u00ecm Y c\u0169ng t\u01b0\u01a1ng t\u1ef1.<\/p>\n\n\n\n
B\u01b0\u1edbc 3: Ta \u0111\u00e1nh c\u1eb7p XY, YX khung 2 ng\u00e0y v\u1edbi t\u1ef7 l\u1ec7 1:3 (ng\u00e0y 1 \u0111\u00e1nh 10 \u0111i\u1ec3m m\u1ed9t con kh\u00f4ng tr\u00fang th\u00ec ng\u00e0y 2 \u0111\u00e1nh 30 \u0111i\u1ec3m m\u1ed9t con).V\u1edbi c\u00e1ch soi c\u1ea7u mi\u1ec5n ph\u00ed t\u1ed5ng hi\u1ec7u n\u00e0y, \u0111\u00e1nh v\u1ec1 th\u00ec d\u1eebng, n\u1ebfu 2 ng\u00e0y kh\u00f4ng v\u1ec1 th\u00ec b\u1ecf.
V\u00ed d\u1ee5: \u1ede ng\u00e0y 23\/05\/2024 ta t\u00ednh \u0111\u01b0\u1ee3c XY = 34. Th\u00ec ng\u00e0y 24-25\/05\/2024 ta \u0111\u00e1nh c\u1eb7p 34,43 th\u00ec ng\u00e0y \u0111\u1ea7u ti\u00ean 24\/05\/2024 \u0111\u00e3 v\u1ec1 34.<\/p>\n\n\n\n
Tr\u01b0\u1eddng h\u1ee3p \u0111\u1eb7c bi\u1ec7t 1:N\u1ebfu A l\u00e0 b\u00f3ng d\u01b0\u01a1ng c\u1ee7a C ho\u1eb7c E l\u00e0 b\u00f3ng d\u01b0\u01a1ng c\u1ee7a C th\u00ec khi t\u00ecm X v\u00e0 Y ta kh\u00f4ng d\u00f9ng ph\u00e9p tr\u1eeb m\u00e0 ta s\u1ebd d\u00f9ng ph\u00e9p c\u1ed9ng.
Ai ch\u01b0a bi\u1ebft b\u00f3ng d\u01b0\u01a1ng th\u00ec xem \u1edf \u0111\u00e2y: b\u00f3ng l\u00f4 \u0111\u1ec1.
V\u00ed d\u1ee5: Ng\u00e0y 22\/05\/2024 Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 82752.
Ta c\u00f3 X = 8-7 = 1.
Khi t\u00ecm Y ta th\u1ea5y C = 7 c\u00f2n E = 2 (7 v\u00e0 2 l\u00e0 b\u00f3ng c\u1ee7a nhau) n\u00ean Y = 7 + 2 = 9
Nh\u01b0 v\u1eady ta t\u00ecm \u0111\u01b0\u1ee3c c\u1eb7p 19,91 \u0111\u00e1nh v\u00e0o ng\u00e0y 23-24\/05\/2024 tr\u00fang 91 ng\u00e0y 2.
L\u01b0u \u00fd: N\u1ebfu tr\u01b0\u1eddng h\u1ee3p 9 v\u00e0 4 l\u00e0 b\u00f3ng c\u1ee7a nhau th\u00ec Y = 9 + 4 = 13 th\u00ec Y = 3.<\/p>\n\n\n\n
Ch\u00fa \u00fd: C\u00f3 m\u1ed9t tr\u01b0\u1eddng h\u1ee3p h\u1ea1n h\u1eefu kh\u00f4ng th\u1ec3 d\u00f9ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u n\u00e0y khi xu\u1ea5t hi\u1ec7n b\u00f3ng nh\u01b0 sau:
N\u1ebfu xu\u1ea5t hi\u1ec7n m\u1ed9t c\u1eb7p t\u1ed5ng hi\u1ec7u l\u00e0 b\u00f3ng c\u1ee7a nhau m\u00e0 ta l\u1ea1i c\u00f3 C = A+ E th\u00ec kh\u00f4ng n\u00ean \u0111\u00e1nh tr\u01b0\u1eddng h\u1ee3p n\u00e0y.<\/p>\n\n\n\n